http://subbot.org/edx/solarenergy/EQE_question.png
PRACTICE QUESTION 3.3.3 (1/1 point)
After the characterization of a solar cell under standard test conditions (STC), the efficiency is 18.6%. What would the efficiency of the solar cell be (in %) if the EQE were halved and all the other external parameters remained the same?
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EXPLANATION
The efficiency depends on the short-circuit current density as:
η=VocJscFFPin
And the short-circuit current density depends on the EQE as:
Jsc=q∫ΦAM1.5(λ)EQE(λ)dλ
Therefore, if the EQE were halved, the Jsc would be halved, and the efficiency would also be halved to η=9.3%.
So, if the EQE is doubled, the efficiency doubles. If you can split an incoming photon into 3 or 4 charge carriers, the efficiency triples, or quadruples. A tripling would already take it past 100% efficiency, if you started at the Shockley-Queisser limit.
So theoretically, conservation of energy doesn't apply. There is no theoretical barrier to getting over 100% efficiency.
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Note: k$5 turned the equations into escape sequences. Once again, the brittleness of the mathematical language is demonstrated.
eta = (V_oc * J_sc * FF) / P_in
J_sc can be increased without theoretical limit, by quantum dots or down conversion or up conversion or hot carriers, etc. Since EQE can go over 100%, J_sc can be doubled, tripled, quadrupled.
If J_sc increases, then eta (the efficiency) increases.
If J_sc triples, and eta started at 33%, eta can go over 100%. In such a case, how is energy conserved? The multiplication of charge carriers seems to create more than the photon on its own could provide.
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MAY I SUCK YOUR PENIS? - Nimey
Hi! I fail at basic sig technology! En plus, je suis pédé! - smegko