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Cleverly Disguised

By DesiredUsername in DesiredUsername's Diary
Fri Feb 15, 2002 at 08:41:43 AM EST
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I have a physics question, but I've cleverly surrounded it with random life stuff so it doesn't look like I'm exploiting this forum for my own ends.


  • I still hate Penny Arcade's new design. The colors are ugly, yes, but I think the worst thing, the thing that is keeping me from reading the news post every day, is the fact that the text is all on the left side. For some reason it makes me feel like I'm standing on my head or wearing my watch on the wrong arm.

  • My work phone number must have previously belonged to a mime that worked for the Dept of Education, judging from 90% of the phone calls I get.

  • I was reading PhysicsWeb today. There was an article about a new technique to measure the dipole of the electron. Hey, I know what a dipole is! This is precisely one of the reasons I started studying physics--so I could read articles like this and have a clue what was going on beyond "day-mn, them thar science dudes shure are smart, hyuck"

  • An electron is constrained to the central axis of the ring of charge of radius R. Show that the electrostatic force exerted on the electron can cause it to oscillate through the center of the ring with an angular frequency

    ω = sqrt(keq/(mR3))

    where q is the ring's charge and m is the electron's mass.

    I understand the problem, but I don't see how I'm equipped to solve it. The only oscillation I've done is SHM (Simple Harmonic Motion) which requires the force to be linearly related to the distance. That's not the case here.


  • The queue's been really empty for the last couple days. I'm not sure what to think about that.

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Cleverly Disguised | 3 comments (3 topical, editorial, 0 hidden)
A slightly dubious approach... (5.00 / 1) (#1)
by mhp on Fri Feb 15, 2002 at 09:54:42 AM EST

From yesterday, you know the magnitude of the field along the axis. Taking a few liberties with the question, we can assume small displacements and hence simple harmonic motion.

For small displacements, i.e. z << R, yesterdays eqn becomes</p>

E = kqz/R3

Multiply this field by e to get the force on an electron, and divide by m to get the acceleration.

Accl = keqz/mR3

Starting to look familiar? You can solve this diff eqn if you like, or you should probably know that an eqn of the form:

x double-dot = something times x

is SHM and has an angular frequency of sqrt(something)

Can you do this without assuming small displacements? I'm not convinced you'd get the same answer - the force falls off after a bit (we found the maximum point yesterday) and this would reduce the frequency (ultimately to zero!)

I think that to get the answer they have given, you need to assume small displacements, although I am happy to be proven wrong...



Cleverly Disguised | 3 comments (3 topical, 0 editorial, 0 hidden)
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